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C Primer Plus Test 5

2020-03-25 12:05 作者:啷個(gè)里格朗郎郎  | 我要投稿

試題來(lái)源:C Primer Plus (第6版)中文版

本章主要為運(yùn)算符、表達(dá)式和語(yǔ)句的測(cè)試題。

5.1 編寫一個(gè)程序,把分鐘表示的時(shí)間轉(zhuǎn)換成用小時(shí)和分鐘表示的時(shí)間。使用#define或const創(chuàng)建一個(gè)表示60的符號(hào)常量或const變量。通過(guò)while循環(huán)讓用戶重復(fù)輸入值,直到用戶輸入小于或等于0的值才停止循環(huán)。

#include<stdio.h>

#include<stdlib.h>

#define TIME 60

int main(){

????int min, h, m;

????printf("Enter the minute:\n");

????scanf("%d", &min);

????while(min > 0){

????????h = min / TIME;

????????m = min % TIME;

????????printf("The time is %d hour %d minute\n", h, m);

????????printf("Enter the minute:\n");

????????printf("If you want to stop it, enter 0 or less 0\n");

????????scanf("%d", &min);

????}

????system("pause");

????return 0;

}

5.1運(yùn)行結(jié)果

5.2編寫一個(gè)程序,提示用戶輸入一個(gè)整數(shù),然后打印從該數(shù)到比該數(shù)大10的所有整數(shù)(例如,用戶輸入5,則打印5~15的所有整數(shù),包括5和15)。要求打印的各值之間用一個(gè)空格、制表符或換行符分開。

#include<stdio.h>

#include<stdlib.h>

int main(){

int num, max;

printf("Enter one number:\n");

scanf("%d",&num);

max = num + 10;

printf("空格:");

while( num <= max){?

printf("%d ",num);

num ++;

}

printf("\n");

num = max - 10;

printf("制表符:");

while( num <= max){?

printf("%d\t",num);

num ++;

}

printf("\n");

num = max - 10;

printf("換行符:");

while( num <= max){?

printf("%d\n",num);

num ++;

}

system("pause");

return 0;

}?

5.2運(yùn)行結(jié)果

5.3編寫一個(gè)程序,提示用戶輸入天數(shù),然后將其轉(zhuǎn)換成周數(shù)和天數(shù)。例如用戶輸入18,則轉(zhuǎn)換成2周4天。以下面的格式顯示結(jié)果:

????18 days are 2 weeks, 4 days.

通過(guò)while循環(huán)讓用戶重復(fù)輸入天數(shù),當(dāng)用戶輸入一個(gè)非正值時(shí)(如0或-20),循環(huán)結(jié)束。

#include<stdio.h>

#include<stdlib.h>

#define W_D 7

int main(){
????int day, weeks, days;

????printf("Enter the number of day:\n");

????scanf("%d", &day);

????while(day > 0){

????????weeks = day / W_D;

????????days = day % W_D;

????????printf("%d days are %d weeks, %d days.\n", day, weeks, days);

????????printf("Enter the number of day:(<=0 to quit)\n");

????????scanf("%d", &day);

????}

????system("pause");

????return 0;

}

5.3運(yùn)行結(jié)果

5.4編寫一個(gè)程序,提示用戶輸入一個(gè)身高(單位:厘米),并分別以厘米和英寸為單位顯示該值,允許有小數(shù)部分。程序應(yīng)該能讓用戶重復(fù)輸入身高,直到用戶輸入一個(gè)非正值。其輸出示例如下:

????Enter a height in centimeters: 182

????182.0 cm = 5 feet, 11.7 inches

????Enter a height in centimeters (<=0 to quit): 168.7

????168.7?cm = 5 feet, 6.4 inches

????Enter a height in centimeters (<=0 to quit): 0

????bye

#include<stdio.h>

#include<stdlib.h>

#define C_F 0.0328

#define F_I 12

int main(){

????float height, inches, c_f, feet;

????int feets;

????printf("Enter a height in centimeters:");

????scanf("%f", &height);

?????while(height > 0){

????????????feet = height * C_F;

????????????feets = (int)feet;

????????????inches = (feet - feets) * F_I;

????????????printf("%.1f cm = %d feet, %.1f inchces\n", height, feets, inches);

????????????printf("Enter a height in centimeters(<=0 to quit):\n");

????????????scanf("%f", &height);

????}

????printf("bye\n");

????system("pause");

????return 0;

}

5.4運(yùn)行結(jié)果

5.5修改程序addemup.c,你可以認(rèn)為addmup.c是計(jì)算20天里賺多少錢的程序(假設(shè)第1天賺$1、第2天賺$2,以此類推)。修改程序,使其可以與用戶交互,根據(jù)用戶輸入的數(shù)進(jìn)行計(jì)算(即,用讀入的一個(gè)變量來(lái)代替20)。

addemup.c

#include<stdio.h>

int main(){
????int count, sum;

????count = 0;

????sum = 0;

????whlle(count ++ < 20)

????????sum = sum + count;

????printf("sum=%d\n",sum);

????return 0;

}

#include<stdio.h>

#include<stdlib.h>

int main(){

????int sum, num, count;

????sum = 0;

????printf("Enter a number:\n");

????scanf("%d", &num);

????count = 0;

????while(count <= num){

????????sum = sum + count;

????????count = count + 1;

????}

????printf("The end is %d\n", sum);

????system("pause");

????return 0;

}

5.5運(yùn)行結(jié)果

5.6修改編程練習(xí)5.5的程序,使其能計(jì)算整數(shù)的平方和(可以認(rèn)為第1天賺$1、第2天賺$4),以此類推。C沒(méi)有平方函數(shù),但是可以用n*n來(lái)表示n的平方。

#include<stdio.h>

#include<stdlib.h>

int main(){

????int sum, count;

????sum = 0;

????printf("Enter a number:\n");

????scanf("%d", &num);

????count = 0;

????while(count ++ < num){

????????sum += count * count;

????}

????printf("%d\n", sum);

????system("pause");

????return 0;

}

5.6運(yùn)行結(jié)果

5.7編寫一個(gè)程序,提示用戶輸入一個(gè)double類型的數(shù),并打印該數(shù)的立方值。自己設(shè)計(jì)一個(gè)函數(shù)計(jì)算并打印立方值。main()函數(shù)要把用戶輸入的值傳遞給該函數(shù)。

#include<stdio.h>

#include<stdlib.h>

double Cbue(double num){

????return (num * num * num);

}

int main(){

????double num;

????printf("Enter a num of double:\n");

????scanf("%lf", &num);

????printf("cbue is %lf\n", Cbue(num));

????return 0;

}

5.7運(yùn)行結(jié)果

5.8編寫一個(gè)方程,顯示求模運(yùn)算的結(jié)果。把用戶輸入的第一個(gè)整數(shù)作為

求模運(yùn)算符的第二個(gè)運(yùn)算對(duì)象,該數(shù)在運(yùn)算過(guò)程中保持不變。用戶輸入

的書是第一個(gè)運(yùn)算對(duì)象。當(dāng)用戶輸入一個(gè)非正值時(shí),程序結(jié)束。

輸出示例如下:

This program computes moduli.

Enter an integer to serve as the second operand:256

Now enter the first operand:438

438 % 256 is 182

Enter next number for first operand (<=0 to quit):1234567

1234567 % 256 is 135

Enter next number for first operand (<=0 to quit):0

Done?


#include<stdio.h>

#include<stdlib.h>

int main(){

int num,f_oper,mod;

printf("This program computes moduli.\n");

printf("Enter an integer to serve as the second operand:");

scanf("%d",&num);

printf("\nNow enter the first operand:");

scanf("%d",&f_oper);

while(f_oper > 0){

mod = f_oper % num;

printf("\n%d %% %d is %d",f_oper,num,mod);

printf("\nEnter next number for first operand (<=0 to quit):");

scanf("%d",&f_oper);

}

printf("Done\n");

return 0;

}

5.8運(yùn)行結(jié)果

5.9編寫一個(gè)程序,要求用戶輸入一個(gè)華氏溫度。程序應(yīng)讀取double

類型的值作為溫度值,并把該值作為參數(shù)傳遞給一個(gè)用戶自定義的

函數(shù)Temperatures()。該函數(shù)計(jì)算攝氏溫度和開氏溫度,并以小數(shù)

點(diǎn)后面兩位數(shù)的精度顯示3種溫度。要使用不同的溫標(biāo)來(lái)表示這3個(gè)

溫度。下面是華氏溫度轉(zhuǎn)攝氏溫度的公式:

攝氏溫度 = 5.0/9.0*(華氏溫度 - 32.0)

開氏溫度常用于科學(xué)研究,0表示絕對(duì)零,代表最低的溫度。下面

是攝氏溫度轉(zhuǎn)開氏溫度的公式:

開氏溫度 = 攝氏溫度 + 273.16

Temperatures()函數(shù)中用const創(chuàng)建溫度轉(zhuǎn)換中使用的變量。在main

函數(shù)中使用一個(gè)循環(huán)讓用戶重復(fù)輸入溫度,當(dāng)用戶輸入q或其他非數(shù)字

時(shí),循環(huán)結(jié)束。scanf函數(shù)返回讀取數(shù)據(jù)的數(shù)量,所以如果讀取數(shù)字則

返回1,如果讀取q則不返回1.可以使用==運(yùn)算符將scanf的返回值和1

作比較,測(cè)試兩值是否相等。?


#include<stdio.h>

#include<stdlib.h>


double Temperatures(double tem){

const double h_s = 5.0/9.0;?

const double s_k = 273.16;

double s_tem, k_tem;

s_tem = (tem - 32.0) * h_s;

k_tem = s_tem + s_k;

printf("%.2lf du\t %.2lf kai\n",s_tem,k_tem);

}


int main(){

double tem;

int status;

printf("Enter a number of huashi:");

status = scanf("%lf",&tem);

while(status == 1){

printf("\n");

Temperatures(tem);

printf("Enter a number of huashi('q' to quit):");

status = scanf("%lf",&tem);

}

printf("Bye\n");

system("pause");

return 0;

}

5.9運(yùn)行結(jié)果


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