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Leetcode 2164. Sort Even and Odd Indices Independently

2023-03-07 15:40 作者:您是打尖兒還是住店呢  | 我要投稿


You are given a?0-indexed?integer array?nums. Rearrange the values of?nums?according to the following rules:

  1. Sort the values at?odd indices?of?nums?in?non-increasing?order.

    • For example, if?nums = [4,1,2,3]?before this step, it becomes?[4,3,2,1]?after. The values at odd indices?1?and?3?are sorted in non-increasing order.

  2. Sort the values at?even indices?of?nums?in?non-decreasing?order.

    • For example, if?nums = [4,1,2,3]?before this step, it becomes?[2,1,4,3]?after. The values at even indices?0?and?2?are sorted in non-decreasing order.

Return?the array formed after rearranging the values of?nums.

?

Example 1:

Input: nums = [4,1,2,3]

Output: [2,3,4,1]

Explanation: First, we sort the values present at odd indices (1 and 3) in non-increasing order. So, nums changes from [4,1,2,3] to [4,3,2,1]. Next, we sort the values present at even indices (0 and 2) in non-decreasing order. So, nums changes from [4,1,2,3] to [2,3,4,1]. Thus, the array formed after rearranging the values is [2,3,4,1].

Example 2:

Input: nums = [2,1]

Output: [2,1]

Explanation: Since there is exactly one odd index and one even index, no rearrangement of values takes place. The resultant array formed is [2,1], which is the same as the initial array.

?

Constraints:

  • 1 <= nums.length <= 100

  • 1 <= nums[i] <= 100

  • easy 題目,運(yùn)用list sort reverse函數(shù)即可

Runtime:?5 ms, faster than?42.52%?of?Java?online submissions for?Sort Even and Odd Indices Independently.

Memory Usage:?42.7 MB, less than?34.55%?of?Java?online submissions for?Sort Even and Odd Indices Independently.


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